Question

A 5.00 liter balloon of gas at 25°C is cooled to 0°C. What is the new volume (liters) of the balloon?

Answer 1

4.58 L.

Step-by-step explanation:

Given that

V₁ = 5 L

T₁ = 25°C = 273 + 25 = 298 K

T₂ = 0°C = 273 K

The final volume = V₂

We know that ,the ideal gas equation

If the pressure of the gas is constant ,then we can say that

`(V_2)/(V_1)=(T_2)/(T_1)`

Now by putting the values in the above equation we get

`V_2=V_1* (T_2)/(T_1)\\V_2=5* (273)/(298)\\V_2=4.58\ L\\`

The final volume of the balloon will be 4.58 L.