Question

Two balls, made of different materials, are rubbed against each other, resulting in 0.30 nC of charge moving from one ball to the other. The balls are then held 0.90 m apart. What is the magnitude of the dipole moment of the two balls?

Answer 1

`5.4* 10^(-10)C-m`

Step-by-step explanation:

We are given that

Charge=
`q=0.30 nC=0.3* 10^(-9) C`

`1 nC=10^(-9)C`

Distance between two balls=l=0.90 m

We have to find the magnitude of dipole moment of the two balls.

We know that

Dipole moment=
`\mid p\mid=2lq`

Where q= Charge

l=Distance between two bodies

Using the formula

Magnitude of dipole moment=
`\mid P\mid=2* 0.3* 10^(-9)* 0.9=5.4* 10^(-10)C-m`

Hence, the magnitude of the dipole moment of the two balls=
`5.4* 10^(-10)C-m`