Question

Below is the DNA strand template for making an mRNA needed to produce a small peptide. a.) Transcribe the sequence into mRNA. (0.5 pt.) b.) Translate the mRNA sequence into protein. (0.5 pt.) c.) Transcribe the mRNA and translate into protein with a mutant sequence that has a transition at position 11. What type of mutation does this cause

Answer 1

a) mRNA: AUG ACC GGC AAU CAA CUA UAU UGA

b) Protein: Methionine, Threonine, Glycine, Asparagine, Glutamine, Leucine, Tyrosine, Stop.

Step-by-step explanation:

The Question was missing the DNA Strand. I have looked up the question and found this to be the DNA strand related to this question. A picture for converting codons to amino acids is also attached. A protein is simply a strand of Amino Acids.

DNA (3 to 5 sequence):

TAC TGG CCG TTA GTT GAT ATA ACT

a). Transcribing to mRNA (5 to 3 sequence):

AUG ACC GGC AAU CAA CUA UAU UGA

b). Related Amino Acids:

1st Codon: Methionine

2nd Codon: Threonine

3rd Codon: Glycine

4th Codon: Asparagine

5th Codon: Glutamine

6th Codon: Leucine

7th Codon: Tyrosine

8th Codon: Stop Codon

c.) DNA with Transition Mutation at Position 11 (5 to 3 sequence):

In genetics, Transition is a point mutation which converts a purine nucleotide to another i.e. A ↔ G, or a pyrimidine nucleotide to another pyrimidine i.e. C ↔ T. Hence, after transition at 11 position, T will be changed to C.

TAC TGG CCG TCA GTT GAT ATA ACT

Transcribing to mRNA (5 to 3 sequence):

AUG ACC GGC AGU CAA CUA UAU UGA

Related Amino Acids:

1st Codon: Methionine

2nd Codon: Threonine

3rd Codon: Glycine

4th Codon: Serine

5th Codon: Glutamine

6th Codon: Leucine

7th Codon: Tyrosine

8th Codon: Stop Codon