How many moles of chromium (lll) nitrate are produced when chromium reacts with 0.85 moles of lead (IV) Nitrate to produce chromium (lll) nitrate and lead?

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asked Jan 23, 2021 37.8k views

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Hakan Baba · Answer 1 · 2021-01-27T02:15:30+0000

Write the equation: 3 Pb(NO3)2 + 2 Cr = 2 Cr(NO3)3 + 3 Pb

By use of mole ratio between Pb(NO3)2 to Cr(NO3)3 which is 3 : 2 the moles of Cr(NO3)3 is therefore
= 0.85 x2 /3 = 0.57 moles

Answer: 0.57 moles
:)

How many moles of chromium (lll) nitrate are produced when chromium reacts with 0.85 moles of lead (IV) Nitrate to produce chromium (lll) nitrate and lead?

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