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2 votes
In triangle ABC of angle A=120 , b=3 a=8 what is B

asked
User Croote
by
7.7k points

1 Answer

5 votes

sinA/a = sinB/b

sin120/8 = sinB/3

3sin120 = 8sinB

3sin120/8 = sinB

sin^-1(3sin120/8) = B

B ≈ 18.951

Hope this helps! ;)

answered
User Zuim
by
8.0k points

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