Question

A car moving eastward along a straight road increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s.

a. What is the carâs average acceleration?
b. What is the carâs average velocity?
c. How far did the car move while accelerating?
Show all of your work for these calculations.

Answer 1

a)
`a= 1.6 m/s^2`

b)V= 24 m/s

c)d=240 m

Step-by-step explanation:

Given that

u = 16 m/s

v= 32 m/s

t= 10 s

The average acceleration = a

We know v = u +at

32 = 16 + a x 10

`a=(32-16)/(10)\ m/s^2`

`a= 1.6 m/s^2`

`d=ut+(1)/(2)at^2`

d=displacement

`d=16* 10+(1)/(2)* 1.6* 10^2`

d=240 m

The average velocity

`V=(d)/(t)`

`V=(240)/(10)\ m/s`

V= 24 m/s

a)
`a= 1.6 m/s^2`

b)V= 24 m/s

c)d=240 m