Question

Nicole throws a ball straight up. Chad watches the ball from a window 6.10m above the point where Nicole released it. The ball passes Chad on the way up, and it has a speed of 12.0m/s as it passes him on the way back down.How fast did Nicole throw the ball?

Answer 1

`v=16.234m/s`

Step-by-step explanation:

Given data

Distance S=6.10 m

Initial Speed u=12.0 m/s

To find

Final Speed v

Solution

From third equation of motion we know that:

`v^(2)-u^(2)=2aS`

where

v is final velocity

u is initial velocity

a is acceleration

S is distance

Substitute the given values to find v

`v^(2)=u^(2)+2aS\\v^(2)=(12.0m/s)^(2) +2(9.8m/s^(2) )(6.10m)\\v^(2)=263.56\\ v=√(263.56)\\ v=16.234m/s`