asked 50.1k views
4 votes
Lim x → ∞ (12x^8-3)/3x^8-2x^7

1 Answer

2 votes

Divide through all terms by the highest power of
x:


(12x^8-3)/(3x^8-2x^7)=\frac{12-\frac3{x^8}}{3-\frac2x}

As
x\to\infty, the terms with
x in the denominator will vanish, leaving us with


\displaystyle\lim_(x\to\infty)(12x^8-3)/(3x^8-2x^7)=\frac{12}3=4

answered
User Kamil Roman
by
8.0k points
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