Question

A foam ball of mass 0.150 g carries a charge of -2.00 nC. The ball is placed inside a uniform electric field, and is suspended against the force of gravity. What are the magnitude and direction of the electric field?

Answer 1

Electric field,
`E=-7.35* 10^5\ N/C` in the direction of gravity.

Step-by-step explanation:

Given that,

Mass of the ball, m = 0.15 g

Charge on the ball,
`q=-2\ nC=-2* 10^(-9)\ C`

The ball is placed inside a uniform electric field, and is suspended against the force of gravity such that,

`mg=qE`

`E=(mg)/(q)`

`E=(0.15* 10^(-3)* 9.8)/(-2* 10^(-9))`

`E=-7.35* 10^5\ N/C`

The electric field will be acting in the direction of gravity. Hence, this is the required solution.