Question

What are the lengths of the other two sides of the triangle?

Answer 1

D

Explanation:

Using sine and cosine ratios in the right triangle and the exact values

sin30° =
`(1)/(2)` and cos30° =
`(√(3) )/(2)`

sin30° =
`(opposite)/(hypotenuse)` =
`(AC)/(AB)` =
`(AC)/(10)` =
`(1)/(2)` ( cross- multiply )

2AC = 10 ( divide both sides by 2 )

AC = 5

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cos30° =
`(adjacent)/(hypotenuse)` =
`(BC)/(AB)` =
`(BC)/(10)` =
`(√(3) )/(2)` ( cross- multiply )

2BC = 10
`√(3)` ( divide both sides by 2 )

BC = 5
`√(3)`