What is the inverse of the given relation? y=7x2 - 3

Question

asked Sep 1, 2021 193k views

1 Answer

Guillermo Carone · Answer 1 · 2021-09-06T08:12:26+0000

Answer:

The inverse of the given relation is
$x=\sqrt{(y+3)/(7)}$ .

Explanation:

Given:

y=7x² - 3

Now, to find the inverse of the given relation.

y=7x^2-3

So, adding both the sides by 3 we get:

y+3=7x^2

Now, dividing both the sides by 7 we get:

(y+3)/(7) =x^2

And, using square root on both the sides we get:

$\sqrt{(y+3)/(7)} =x$

Thus:

$x=\sqrt{(y+3)/(7)}$

Therefore, the inverse of the given relation is
$x=\sqrt{(y+3)/(7)}$ .