Question

how many liters of a 60% antifreeze solution must be added to 8L of a 10% antifreeze solution to produce a 20% antifreeze solution?

Answer 1

Answer: 2Liters

Step-by-step explanation:

The expression used will be :

`M_1V_1+M_2V_2=M_3V_3`

where,

`M_1` = concentration of first antifreeze= 60%

`M_2` = concentration of second antifreeze= 10%

`V_1` = volume of first antifreeze = x L

`V_2` = volume of second antifreeze = 8 L

`M_3` = concentration of final antifreeze solution= 20%

`V_3` = volume of final antifreeze = (x+8) L

Now put all the given values in the above law, we get the volume of antifreeze added

`60* x+10* 8=20* (x+8)`

`x=2L`

Therefore, the volume of 60% antifreeze solution that must be added is 2L