asked 65.0k views
2 votes
The equation for the circle below is x^2+ y^2= 81. What is the length of the
circle's radius?

2 Answers

5 votes

Answer: 9

Step-by-step explanation: The standard form of an equation of a line:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

x^2+y^2=81\Rightarrow(x-0)^2+(y-0)^2=9^2

Therefore

center: (0, 0)

radius: r = 9

answered
User Jay Mungara
by
7.7k points
4 votes

Answer:

9

Explanation:

The standard form of an equation of a line:


(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:


x^2+y^2=81\Rightarrow(x-0)^2+(y-0)^2=9^2

Therefore

center: (0, 0)

radius: r = 9

answered
User Deric Lima
by
7.9k points

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