asked 45.3k views
3 votes
The specific heat of a certain type of cooking oil is 1.75 J / ( g ⋅ ° C ) . 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of 2.76 kg 2.76 kg of this oil from 23 ° C 23 °C to 191 ° C?

asked
User Expoter
by
9.2k points

1 Answer

3 votes

Answer:

811.44 kJ

Step-by-step explanation:

specific heat, c = 1.75 J/g °C

mass, m = 2.76 kg

T1 = 23 °C

T2 = 191 °C

Heat required, H = m x c x ΔT

H = 2.76 x 1.75 x 1000 x (191 - 23)

H = 811440 J

H = 811.44 kJ

Thus, the amount of heat required is 811.44 kJ.

answered
User Psurikov
by
8.7k points
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