The length of rectangle is 44 yards and width of rectangle is 20 yards
Solution:
Let the length of rectangle be "a"
Let the width of rectangle be "b"
Rectangle has a length that is 4 more than twice the width
Length = 4 + 2(width)
Length = 4 + 2b
The perimeter is 128 yards
The perimeter of rectangle is given by:
Perimeter = 2(length + width)
128 = 2(4 + 2b + b)
128 = 2(4 + 3b)
Divide both sides by 2
64 = 4 + 3b
3b = 60
b = 20
Substitute b = 20 in length
Length = 4 + 2(20)
Length = 4 + 40 = 44
Thus length of rectangle is 44 yards and width of rectangle is 20 yards