Question

A chemist prepares a solution of barium chlorate BaClO32 by measuring out 42.g of barium chlorate into a 500.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's barium chlorate solution. Be sure your answer has the correct number of significant digits.

Answer 1

so sorry I'm not sure hopefully you will et someone to help :)

Answer 2

The concentration is 0.276 M

Step-by-step explanation:

Step 1: Data given

Mass of Ba(ClO3)2 = 42.0 grams

Molar mass of Ba(ClO3)2 = 304.23 g/mol

Volume = 500 mL = 0.500 L

Step 2: Calculate moles Ba(ClO3)2

Moles Ba(ClO3)2 = mass Ba(ClO3)2 / molar mass Ba(ClO3)2

Moles Ba(ClO3)2 = 42.0 grams / 304.23 g/mol

Moles = 0.138 moles

Step 3: Calculate molarity

Molarity = moles Ba(ClO3)2 / volume

Molarity = 0.138 moles / 0.500 L

Molarity = 0.276 M

The concentration is 0.276 M