Question

Cai collected 2 1/2 times as much as mark. Mark collected 2/3 as much as Jen.who collected the most? Who collected the least? Explain

Answer 1

Cai collected most and Mark collected least

Solution:

Let Jen collected be "x"

Given that,

Mark collected 2/3 as much as Jen

`\text{Mark collected } = (2)/(3) * \text{Jen collected}\\\\\text{Mark collected } = (2)/(3) * x\\\\\text{Mark collected } = (2x)/(3) = 0.67x`

Also given that,

Cai collected 2 1/2 times as much as mark

Therefore,

`\text{Cai collected } = 2(1)/(2) * \text{ mark collected }\\\\\text{Cai collected } = 2(1)/(2) * (2x)/(3)\\\\\text{Cai collected } = (5)/(2) * (2x)/(3)\\\\\text{Cai collected } = (5x)/(3) = 1.67x`

Who collected the most? Who collected the least?

Jen collected = x

Mark collected = 0.67x

Cai collected = 1.67x

Thus,

1.67x > x > 0.67x

Thus, Cai collected most and Mark collected least