Question

If the theoretical yield of the reaction below corresponds to 71.0 g and the percent yield of the reaction is known to be reproducibly 81.1%, calculate the actual yield. Given: Li2O+H2O→2LiOH

Answer 1

m = 57.581 g

Step-by-step explanation:

The actual yield or experimental yield of a reaction is always calculated using the theorical yield and the experimental, using the following expression:

%yield = Exp yield/theo yield * 100 (1)

If we know the theorical yield and the percent of yield, we can calculate the experimental or actual yield by solving the expression above:

Exp yield = %yield * theo yield/100

Replacing the values we have:

Exp yield = 81.1 * 71 / 100

Exp yield = 57.581 g

And this would be the actual yield of the reaction