Question

Please help with #20

Answer 1

`\bf 27x^2y^3z+12xy^2z\qquad \begin{cases} 27=&3\cdot 3\cdot 3\\ x^2=&x\cdot x\\ y^3=&y\cdot y\cdot y\\ z =&z\\ \cline{1-2} 27x^2y^3z=&3\cdot 3\cdot \underline{3x} xy\underline{yyz} \end{cases}~\hfill \begin{cases} 12=&2\cdot 2\cdot 3\\ x=&x\\ y^2=&y\cdot y\\ z=&z\\ \cline{1-2} 12xy^2z=&2\cdot 2\cdot \underline{3xyyz} \end{cases} \\\\\\ \stackrel{\mathbb{GCF}}{3xyyz\implies 3xy^2z}~\hfill \stackrel{\textit{common factoring}}{3xy^2z(9xy~~+~~4)}`