Question

In order to solve the system of equations below, Harvey multiplies each equation by a constant to eliminate the x terms.

7 x + 3 y = 5. 2 x + 5 y = negative 11.

What are the resulting equations?
14 x + 6 y = 10. Negative 14 x minus 35 y = 77.
14 x + 6 y = 10. Negative 14 x + 35 y = 77.
14 x + 6 y = 10. Negative 14 x minus 35 y = negative 77.
Negative 14 x minus 6 y = 10. 14 x + 35 y = negative 77.

Answer 1

A

Explanation:

i did it on edge and got it right

Answer 2

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

Explanation:

Let's find out the constants to eliminate the x terms

7 x + 3 y = 5

2 x + 5 y = negative 11

Let's multiply the first equation by 2 and the second one by -7, this way:

2 * (7 x + 3 y = 5)

-7 * (2 x + 5 y = negative 11)

14x + 6y = 10

-14x - 35y = 77

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77