Question

After crossing true-breeding yellow and green pea plants, Mendel allowed the yellow F1 plants to self. As a result of this F1 self-cross, he observed 5920 yellow peas and 2103 green pea plants. Determine whether or not these data are consistent with his law of equal segregation.

Answer 1

The data are not consistent with law of equal segregation.

Step-by-step explanation:

According to law of segregation, the ratio of yellow peas to green peas at F2 should be 3:1.

yellow green

Observed frequencies 5920 2103

Expected frequency
`(3)/(4)*8023` = 6017.25
`(1)/(4) * 8023` = 2005.75

Using Chi square(
`X^2`):

`X^2` yellow =
`((observed frequency - expected frequency)^2)/(expected frequency)`

=
`((5920 - 6017.25)^2)/(6017.25)`

= 1.57

`X^2` green =
`((2103 - 2005.75 )^2)/(2005.75 )`

= 4.72

`X^2` total = 1.57 + 4.72 = 6.29

Degree of freedom = 2 - 1 = 1

`X^2` tabulated (α = 0.05) = 3.841

The calculated Chi square value is more than the tabulated Chi square value, hence, the conclusion is that the data are not consistent with law of segregation.