Determine the tension developed in cord DE required for equilibrium of the lamp. Express your answer to three significant figures and include the appropriate units.

Question

asked Aug 23, 2021 200k views

1 Answer

Talbot · Answer 1 · 2021-08-28T20:59:21+0000

Answer:

Fde = 1080 N (3 sig fig)

Step-by-step explanation:

Taking point E

Sum of forces at E in x direction:

Fde cos (30) - Fcd = 0 ..... Eq 1

Sum of forces at E in y direction:

Fde sin (30) - Wf = 0 ..... Eq 2

Wf = m*g = 55 * 9.81 = 539.55 N

Using Eq 2 to evaluate Fde

Fde = Wf / sin (30) = 539.55 / sin (30) = 1079.1 N

Answer: Fde = 1080 N (3 sig fig)