asked 56.0k views
2 votes
In a​ year, almost a billion people on the planet​ didn't have access to clean drinking water. If there were 5.35.3 times ×10 Superscript 9109 people in the​ world, then approximately what percent of them lived without clean drinking​ water?

asked
User Sheilagh
by
7.4k points

1 Answer

2 votes

Answer:

Approximately 18.7% people lived without clean drinking​ water.

Explanation:

Given:

Total Number of people living in the world =
5.35*10^9

Number of people didn't have access to clean drinking water =
1*10^9

We need to find the approximately what percent of them lived without clean drinking​ water.

Solution:

Now we can say that;

To find the percent of people lived without clean drinking​ water can be calculated by Number of people didn't have access to clean drinking water divided by Total Number of people living in the world multiplied by 100.

framing in equation form we get;

percent of people lived without clean drinking​ water =
(1*10^9)/(5.35* 10^9)* 100 \approx 18.7\%

Hence Approximately 18.7% people lived without clean drinking​ water.

answered
User Yzerman
by
8.4k points
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