Question

How long must a current of 100mA flow so as to transfer a charge of 80 C? ​

Answer 1

800s

Step-by-step explanation:

Q=It

where,

Q=80c

I =100MA=0.1A

t=?

Q=It

800=0.1×t

t=80×0.1

t=800s

Answer 2

800 secs

Step-by-step explanation:

Q = it

80 = 100 x10^-3 t

t = 80/0.1

= 800secs