If 9\geq4x+19≥4x+19, is greater than or equal to, 4, x, plus, 1, which inequality represents the possible range of values of 12x+312x+312, x, plus, 3?

Question

asked Sep 6, 2021 44.4k views

1 Answer

Otello · Answer 1 · 2021-09-12T20:10:36+0000

Answer:

$12x+3\leq 27$

Explanation:

It is given that

$9\geq4x+1$

We need to find the possible range of values of 12x+3.

Subtract -1 from both sides.

$9-1\geq 4x$

$8\geq 4x$

Multiply both sides by 3.

$24\geq 12x$

Add 3 on both sides.

$24+3\geq 12x+3$

$27\geq 12x+3$

It can be rewritten as

$12x+3\leq 27$

Therefore, 12x+3 must be less than or equal to 27.