Question

Two 10-Hz, sine waves have a relative phase shift of 30 deg. What is the time difference between them? If the frequency of these sine waves doubles, but the time difference stays the same, what is the phase difference between them?

Answer 1

The time difference is 8.33 ms.

The phase difference between them is 60°

Step-by-step explanation:

Given that,

Frequency = 10 Hz

Angle = 30°

We need to calculate the time difference

Using formula of time difference

`\Delta t=(\phi)/(360^(\circ)* f)`

Put the value into the formula

`\Delta t=(30)/(360*10)`

`\Delta t=8.33\ ms`

If the frequency of these sine waves doubles, but the time difference stays the same,

`f=20\ Hz`

We need to calculate the phase difference between them

Using formula of phase difference

`\Delta \phi=\Delta t*360* f`

Put the value in to the formula

`\Delta=8.33*10^(-3)*360*20`

`\Delta \phi=60^(\circ)`

Hence, The time difference is 8.33 ms.

The phase difference between them is 60°