Question

Write the slope -intercept form of an equation of the line that passes through the given point and is parallel to the graph of the equation.

5,-5,3x+y=-2

A. y=10x+3
B. y=-3x+10
C. y=1/3x-10
D. y=-3x-10

Answer 1

The equation of the required line in the slope-intercept form is

y = -3x + 10

Explanation:

i) the required line passes through the point (5, -5)

ii) the required line is also parallel to the line 3x + y = -2 ⇒ y = -3x - 2

Therefore the slope of the given line is -3.

Therefore the slope of the required line is also -3

The equation of the required line in the slope-intercept form is

y - (-5) = -3(x - 5) ⇒ y + 5 = -3x + 15 ⇒ y = -3x + 10 ∴ 3x + y = 10.