asked 110k views
0 votes
You are provided with a fuel cell that is designed to operate at j = 3 A∕cm2 and P = 1.5 W∕cm2. How much fuel cell active area (in cm2) is required to deliver 2 kW of electrical power? (This is approximately enough to provide power to the average American home.)

(a) 296.3 cm2
(b) 1333.3 cm2
(c) 444.4cm2
(d) 666.6 cm2

asked
User Govert
by
7.3k points

1 Answer

4 votes

Answer:

correct option is b) 1333.3 cm²

Step-by-step explanation:

given data

power P = 1.5 W∕cm²

j = 3 A∕cm²

electrical power = 2 kW

solution

as given 1.5 W∕cm² power mean 1.5 W power operated by 1 cm²

so here 2 kW i.e here 2000 W power is operated in

2000 W power is operated =
(2000W*1cm^2)/(1.5W)

= 1333.33 cm²

so correct option is b) 1333.3 cm²

answered
User Peter Bennink
by
7.9k points

No related questions found