Question

Calculate the period of a ball tied to a string of length 0.468 m making 3.8 revolutions every second. Answer in units of s. Your answer must be within ± 2.0%

Answer 1

0.26315 s

Step-by-step explanation:

The frequency of the ball tied to a string system is 3.8 rev/s.

That means in one second the ball will complete 3.8 revolutions.

The time period will be the reciprocal of this frequency

`T=(1)/(f)\\\Rightarrow T=(1)/(3.8)\\\Rightarrow T=0.26315\ s`

The time period is 0.26315 s

It can be also solved in the following way

`1\ s=3.8\ rev\\\Rightarrow 1\ rev=(1)/(3.8)\ s\\\Rightarrow 1\ rev=0.26315\ s`

The time period is 0.26315 s