Question

Find the first four terms of each sequence.

F(n) = 3n - 1

Answer 1

2, 5, 8, 11

Explanation:

F(n) = 3n - 1

put n=1

F(1) = 3(1) - 1 = 2

put n=2

F(2) = 3(2) - 1 = 6 - 1 = 5

put n=3

F(3) = 3(3) - 1 = 9 - 1 = 8

put n=4

F(4) = 3(4) - 1 = 12 - 1 = 11