Answer: The question is incomplete without values, but here is a similar questions that has values ; A chemist adds 85.0mL of a 0.125 mol/L aluminum sulfate (Al2(S04)solution to a reaction flask . Calculate the millimoles of aluminum sulfate the chemist has added to the flask . Be sure your answer has the correct number of significant digits mmol.
Number of moles = 10.625millimoles or 1.06 x 10 millimoles.
Step-by-step explanation :
From number of moles = concentration (mol/L) x volume (L)
Concentration = 0.125mol/L, Volume = 85.0mL ( Convert to L) = 85/1000 = 0.085L
Substitute in the equation = 0.125mol/L x 0.085L = 0.010625moles
But 1mole is equivalent to 1000millimoles
convert the 0.010625moles to millimoles = 0.010625moles x 1000millimoles/1mole
Number of moles = 10.625millimoles or 1.06 x 10 millimoles.