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Please help... I have no clue

Please help... I have no clue-example-1
asked
User Shanimal
by
8.0k points

1 Answer

7 votes

Answer:

OPTION C: Sin C - Cos C = s - r

Explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that:
$ \textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}} $

and
$ \textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}} $

Given, Sin B = r and Cos B = s


$ Sin B = r = (opp)/(hyp) = (AC)/(BC) = (AC)/(h) $


$ \textbf{AC} = \textbf{rh} $

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.


$ Cos B = s = (adj)/(hyp) = (AB)/(BC) = (AB)/(h) $


$ \textbf{AB} = \textbf{sh} $

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.


$ Sin C = (opp)/(hyp) $


$ Sin C = (AB)/(BC) $


$ = (sh)/(h) $

= s

Sin C = s


$ Cos C = (adj)/(hyp) $


$ \implies Cos C = (AC)/(BC) $

⇒ Cos C =
$ (rh)/(h) $

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

answered
User Chris Michael
by
8.5k points

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