Question

5. An attacker swings a board with a mass of 2 kg toward a victim. The acceleration is 10 m/s2 when the board hits the victim. How much force did the board exert on the victim? Obj. 7.2​

Answer 1

The force exerted on victim is 20 newton

Solution:

An attacker swings a board with a mass of 2 kg toward a victim

The acceleration is 10
`m/s^2` when the board hits the victim

To find: Force exerted on victim

The force is given by formula:

`F = mass * acceleration`

From given,

`mass = 2 \text{ kg }\\\\Acceleration = 10`
`m/s^2`

Substituting the values in formula,

`Force = 2 * 10 = 20`

Thus force exerted on victim is 20 newton