Question

a number consisting of two digits exceeds 4 times the sum of the digits by 3 .if 27 is added to the number, the place of the digits of the number are interchanged, find the number. ​

Answer 1

47

Explanation:

We can take x to represent the 10s digit and y the ones digit. Then we have ...

(10x +y) - 4(x+y) = 3. . . . . a number exceeds 4 times the digit sum by 3

(10x +y) +27 = (10y +x) . . . . . adding 27 swaps the digits

Simplifying these equations to standard form gives ...

2x - y = 1

x - y = -3

Subtracting the second equation from the first gives ...

x = 4

y = 2x -1 = 7

The number is 47.