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5 votes
How many moles of Pb(no3)3 will be required to react with 0.64 mole of KCl?

KCl + pb(NO3)3 _ kNO3 + PbCl

asked
User Bsoundra
by
8.0k points

1 Answer

2 votes

2KCl + Pb(NO3)2 -> 2KNO3 + PbCl2

(mole) 0,64 0,32

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