Question

Writing a pressure equilibrium constant expression Ammonia and oxygen react to form nitrogen monoxide and water, like this: 4 NH3(g)+5 O2(g)-4 NO(g)+6 H2O(g) Write the pressure equilibrium constant expression for this reaction.

Answer 1

Answer: The equilibrium constant expression for the given equation is written below.

Step-by-step explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_(p)`

For the general chemical equation:

`aA+bB\rightleftharpoons cC+dD`

The expression of
`K_p` follows:

`K_p=(p_C^c* p_D^d)/(p_A^a* p_B^b)`

For the given chemical equation:

`4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)`

The expression of
`K_p` for above equation follows:

`K_p=((p_(H_2O)^5)* (p_(NO)^4))/((p_(NH_3)^4)* (p_(O_2)^5))`

Hence, the equilibrium constant expression for the given equation is written above.