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How many four-digit numbers are there formed from the digits 1, 2, 3, 4, 5 (with possible repetition) that are evenly divisible by 4?

asked
User Allana
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8.5k points

1 Answer

7 votes

Answer:

80 four-digit numbers are there which is divisible by 4.

Explanation:

Consider the provided information.

A number is divisible by 4 if the last 2 digits are divisible by 4.

So the possible last 2 digits are:

xx12, xx24, xx32, xx44, xx52

In each case, for first two number we have 4 choices and last 2 choices are fixed.

Therefore, the total number of ways are: 5(4×4)

Where 5 represents possible case in which last 2 digits are divisible by 4.

the total number of ways are: 5(4×4)=80

Hence, 80 four-digit numbers are there which is divisible by 4.

answered
User Marcs
by
8.0k points

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