Question

What is the first term of the quotient for the division problem (8x2−4x+3)÷(x−3)?

Answer 1

The first term of the quotient is
`8x`.

Explanation:

Given,

Dividend =
`8x^2-4x+3`

Divisor =
`x-3`

We have to find out the first term of the quotient.

We have attach the figure for your reference.

Solution,

Step 1:

On dividing
`8x^2-4x+3` by
`x-3` the quotient is
`8x` and remainder is
`20x+3`.

Step 2:

Now we divide
`20x+3` by
`x-3` the quotient is 20 and the remainder is 63.

So the solution of the division
`8x^2-4x+3` ÷
`x-3` is;

quotient =
`8x+3`

and remainder =
`63`

Hence the first term of the given division is
`8x`.