Question

Find the missing coefficient in the equation of the line that passes through the given point. Then write the equation in standard form.

1. -4x+By=7; (-1,1)
2. Ax+y= -3; (2,11)

Answer 1

1)B= 3 ; standard form y = 4x/3 + 7/3 2)A= -7 ; standard form y = 7x -3

Explanation:

1.) We can substitute the coordinates of the known point of the line:

-4x + By = 7 ; (-1,1)

-4(-1) + B(1) = 7

4 + B = 7

B = 7- 4 = 3

-4x + 3y = 7

y = (4x + 7)/3

Equation 1 in standard form:

1.) y = 4x/3 + 7/3

2.) We can substitute the coordinates of the known point of the line:

Ax + y = -3 ; (2,11)

A(2) + (11) = -3

2A + 11 = -3

2A = -3 -11 = -14

A = -14/2 = -7 coefficient A

-7x + y = -3

Equation 2 in standard form:

2.) y = 7x -3

Answers:

1) B= 3 ; standard form y = 4x/3 + 7/3 2) A= -7 ; standard form y = 7x -3

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