Question

if sin A = - Squareroot 3/4 and angle A is in the third quadrant, determine the exact value of tan A.

Answer 1

tan(A) = √3

Explanation:

In the third quadrant, the tangent is positive. For sin(A) = -√(3/4), the tangent is ...

`tan(A)=(sin(A))/(cos(A))=\frac{-\sqrt{(3)/(4)}}{-\sqrt{1-\left(\sqrt{(3)/(4)}\right)^2}}=\sqrt{(\left((3)/(4)\right))/(\left((1)/(4)\right))}\\\\tan(A)=√(3)`