Question

If secA=2/√3 find the value of tanA/cosA+1+sinA/tanA

Answer 1

(10 + 3√3) / 6.

Explanation:

cosA = 1/secA = 1 / 2/√3 = √3 /2.

If we consider a 30-60-90 triangle if cosA = √3/2, sinA = 1/2 and

tanA = 1/√3.

So the answer is:

1/√3 / √3 /2. + 1 + 1/2 / 1/√3

= 2/3 + 1 + √3/2

= 5/3 + √3 /2

= (10 + 3√3) / 6.