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The electrostatic force of attraction between two charged objects separated by a distance of 1.0 cm is given by F. If the distance between the objects were increased to 5.0 cm, what would be the electrostatic force of attraction between them?

a) 5Fb) F/5c) 25Fd) F/25

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User Zeeng
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1 Answer

2 votes

Answer:

D. F/25

Step-by-step explanation:

F= kq1q2/r² when r= 1,when r = 5,

F= F/5²

Force= F/25

answered
User Sylwester
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