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Rank the following compounds in order of decreasing boiling point: potassium bromide (KBr), acetylene (C2H2), and chloromethane (CH3Cl)

asked
User MarrLiss
by
7.2k points

1 Answer

2 votes

Answer:

KBr , CH3Cl, C2H2

Step-by-step explanation:

Chloro-methane or Chloroform exist as a dense liquid, acetylene as a gas used for welding purpose and potassium bromide is a crystalline solid, the states of matter of each of them gives us a clue of how strong the bonds between them are , acetylene having the weakest bond as its a gas and KBr having the strongest bond for its crystalline solid state. The boiling point of each compound is given below;

C2H2 =61.2°C

CH3Cl =-192.2°C

KBr =1435°C

answered
User Ravi Sankar Raju
by
7.7k points
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