Question

:-QUESTION:-

*AD is a diameter of a circle and AB is a chord if AD = 34 cm, AB = 30 cm then find the distance of AB from the centre of chord.*​
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Answer 1

`\sf AB \longrightarrow \sqrt{ {34}^(2) - {30}^(2) }`

`\sf AB \longrightarrow √((34 * 34) - (30 * 30))`

`\sf AB \longrightarrow √(1.156 - 900)`

`\sf AB \longrightarrow √(256)`

`\sf AB \longrightarrow \sqrt{ {16}^(2) }`

`\sf AB \longrightarrow 16 ~cm`