A hint is to plug in the x-value then do exponents first then multiply.
For example:
y = 2(5)^x
We are given x = 2, we must find y.
y = 2(5²)
y = 2(25)
y = 50
* Keep in mind that when you do a negative exponent, you have to swap it to make it positive:
5^-2 is the same as 1/(5^2)...