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It p(x) = x2 - 1 and 0(X) - 5(x-1), which expression is equivalent to (0-2)(x)? 5(x - 1) - x2 - 1 (5x - 1) - (x2 - 1) (x2 - 1) - 5(x - 1) (x2 - 1) - 5x - 1

It p(x) = x2 - 1 and 0(X) - 5(x-1), which expression is equivalent to (0-2)(x)? 5(x - 1) - x2 - 1 (5x - 1) - (x2 - 1) (x2 - 1) - 5(x - 1) (x2 - 1) - 5x - 1
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It p(x) = x2 - 1 and 0(X) - 5(x-1), which expression is equivalent to (0-2)(x)?

5(x - 1) - x2 - 1
(5x - 1) - (x2 - 1)
(x2 - 1) - 5(x - 1)
(x2 - 1) - 5x - 1

asked
User Marko Rochevski
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8.5k points

1 Answer

7 votes

Answer:

(x2 - 1) - 5x - 1

Explanation:

answered
User SmokeDetector
by
8.3k points
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