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A function f is defined by f(x)= 3/17x+2. If x increases by 51, by how much does f(x) increase?

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if x increases by 51, f (x) increases by 9.

Explanation:

Given function:


f(x)=(3)/(17) x+2

The above equation would have a constant slope as it seems to be a linear function. ‘x’, the coefficient of the variable x is the slope of the function. Here,


x=(3)/(17)

The rate of change of the function with respect to x referred as the slope of the function. Thus,


slope =\frac{\text { change of } f(x)}{\text { change of } x}


(\Delta f)/(\Delta x)=(3)/(17)

Given, x increases by 51. So, we have


\Delta x=51


(\Delta f)/(51)=(3)/(17)

Now solve for ΔF,


\Delta f=(3)/(17) * 51=3 * 3=9

Thus, we have obtained that if x increases by 51, f (x) increases by 9.

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