Question

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

y=14x+92

y=−4x−12

y=14x+114

y=−4x−4

Answer 1

Answer:D. y=−4x−4

Explanation:

Answer 2

The Correct option is Last one
`y=-4x-4`

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line
`y=-4x-3` is
`y=-4x-4`

Explanation:

Given:

`y=-4x-3`

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

`y=-4x-3` ..........Given

Comparing with Slope-Intercept form,

`y=mx+c`

Where m =slope

We get

`Slope = m = -4`

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

`(y-y_(1))=m(x-x_(1))`

Substituting the points and so we will get the required equation of the line,

`(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line`

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line
`y=-4x-3` is
`y=-4x-4`