Question

At a school, 43% of students attend the homecoming football game. Only 23% of students go to the game and the homecoming dance. What is the probability that a student who attends the football game also attends the dance?

Answer 1

The probability that a student who attends the football game also attends the dance is 23/43 or approximately 0.535.

Step-by-step explanation:

To find the probability that a student who attends the football game also attends the dance, we can use the given information. We know that 43% of students attend the football game, and 23% of students attend both the game and the dance.

To calculate the probability, we can divide the number of students who attend both the game and the dance by the number of students who attend the game.

Let's say there are 100 students in total. Then, 43 students attend the game, and 23 students attend both the game and the dance. Therefore, the probability that a student who attends the football game also attends the dance is 23/43 or approximately 0.535 (rounded to three decimal places).

Answer 2

0.535

Step-by-step explanation:

Let students that attend homecoming = H

Let students that attend football game = F

Pr(H) = 43% = 0.43

Pr (H and F) = 23% = 0.23

For conditional probability,

Pr(H and F) = Pr(H) * Pr(H|F)

Pr(H|F) = Pr(H and F) / Pr(H)

=0.23/0.43

Pr(H|F) = 0.535

The probability that a student attends football game and also attends dance = 0.535