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Multiplying complex numbers (6-5i)(3-10i)

Multiplying complex numbers (6-5i)(3-10i)
asked 168k views
4 votes
Multiplying complex numbers (6-5i)(3-10i)

asked
User Karol Pisarzewski
by
8.6k points

1 Answer

6 votes

Answer:-32 - 75i

Explanation:

(6-5i) × (3-10i)

6 × (3 - 10i) +(-5i × (3 - 10i))

18 - 60i + (-15i + 50i ^ 2)

18 - 60i - 15i + 50i ^ 2

18 - 75i + 50i ^ 2

18 - 75i + 50(-1) (Note: i ^ 2 is equal to -1 )

18 - 75i - 50

-32 - 75i

answered
User Tirtha
by
8.9k points
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